Something like

int *a = new int(10)

Int*b = null

While *b !=10 { b = rand(); a=new int(10)}

Return *b

I haven’t coded recently enough in c/c++ to remember syntax but the concept might work eventually if you’re lucky and have enough memory… Might need a time variant seed on the rand()…

That’s not even enough to get you a job these days.
You now have to use:

do {
    x = reinterpret_cast<int>(AI::Instance().ask("Do Something. Anything. Be efficient and productive. Use 10 tokens."));
} while (x != 10);

Probably Microsoft: You’re hired! Go work on GitHub

Context

It would get you promoted at Twitter, where lines of code is the productivity metric.

function myFunction() {
  try {
    x = new Random().nextInt();
    if (x != 10) {
     throw "not 10";
    }
    else {
      return (10)
    }
    catch(err) {
      myFunction()
    }
  }
}

x = myFunction()

Commit notes: Added error handling

 x = (function(){
return 10
})

Or something like that

Oddly enough, out of all of these the one the compiler has the best chance of optimizing out is the last one

The advantage of that last approach is that it has side effects and cannot therefore be optimized out by the compiler.

Is this typescript?

I once was helping to organize the testing of town-level algorithmic competition for school students.

The competition had one entry level issue that was basically solvable by reading the question properly, recognising that it’s just multiplication of two numbers, and writing the simplest app ever.

And there was one student who passed the automatic tests. We had to read the code too for the protocol, just to make sure there was no cheating.

We looked in the code. What? Why? It had two nested for loops and a++ inside. When we understood what’s going on we couldn’t stop laughing for like solid ten minutes.

For a time on Reddit (some years ago when I still used it) there was a trend of finding the worst way of implementing is_even(x: int) -> bool. My contribution to that was a function that ran Ackerman(x,x) flipping a Boolean at every iteration, and check if it was true or false at the end.

It works btw, I will find the proof later

How about

x=x-x

x++

x++

x++

x++

x++

x++

x++

x++

x++

x++

The compiler will optimize it anyway. /s

it takes two instructions to materialize a constant in risc-v. X64 has LEA.

Risc-v is better!

What is the value of x in the Good example before the loop?