sexy_peach@feddit.deM to Memes@lemmy.mlEnglish · 2 年前soak and jump humpfeddit.deimagemessage-square154fedilinkarrow-up1817arrow-down123
arrow-up1794arrow-down1imagesoak and jump humpfeddit.desexy_peach@feddit.deM to Memes@lemmy.mlEnglish · 2 年前message-square154fedilink
minus-squaredriving_crooner@lemmy.eco.brlinkfedilinkarrow-up25arrow-down1·edit-22 年前Did you mean oron?
minus-squareNoIWontPickaName@kbin.sociallinkfedilinkarrow-up9·2 年前I can’t tell if that is a purposeful typo or not.
minus-square_danny@lemmy.worldlinkfedilinkarrow-up4·edit-22 年前Technically it’d need to be: mormon / 2m = oron
minus-squaredriving_crooner@lemmy.eco.brlinkfedilinkarrow-up4·2 年前A word isn’t a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B)
minus-square_danny@lemmy.worldlinkfedilinkarrow-up2·2 年前You’re right, that would be more technically correct.
minus-squarethemusicman@lemmy.worldlinkfedilinkarrow-up1·edit-22 年前If words are an ordered set, then mormon = morn Words are a base 27 integer. (mormon - mon) / a000 + on = moron
Did you mean oron?
I can’t tell if that is a purposeful typo or not.
mormon - 5*n = Oro
Technically it’d need to be:
mormon / 2m = oron
A word isn’t a product of letters, that would made mormon = nomorm, but an ordered set, where the subtract operation gives you the first set without any element also found on the second set (in set notation A-B = A-(A intersection B)
You’re right, that would be more technically correct.
If words are an ordered set, then mormon = morn
Words are a base 27 integer. (mormon - mon) / a000 + on = moron
Perhaps…